Monday, July 13, 2015

Lab 11A: Specific Heat of a Metal





Summary
The purpose of this lab was to find the identity of an element by calculating the specific heat. I found the specific heat of the element by calculating the amount of energy by the change in room temperature and the water heated by the metal block. Then, I divided the amount of energy by the change in room temperature and the water heated by the metal block values multiplied. These calculations can be connected to the equation Q=m*change in temperature*c. We got the needed information to perform our calculations from boiling water with the metal block. We got 1.2 J/gC for our specific heat. My partner and I concluded that Metal A was Lead from our calculations. 

Data
We only figured out the identity of one metal, hence the data below is for Metal A.

Mass of Styrofoam Cup- 7.65 g
Mass of cup + water- 301.7 g
Mass of water- 294.05 g
Initial temperature of H2O in a cup- 23.1 C
Initial temperature of metal in boiling water- 97.0 C
Final temperature of metal and water- 24.8 C
Mass of metal alone- 250.2 g






No comments:

Post a Comment