Procedure
First, we had to figure out the mass of the aluminum which we received. Then, we calculated the mass of the aluminum by calculated the water displacement in a graduated cylinder. From this we divided the mass and the volume to get the density. Then, we measured the length and width of the aluminum foil in centimeters. In this case, height was the thickness of the aluminum foil. We also had to find the mass of the aluminum foil, which we weighed on the weighing scale. Since density=mass/volume we then plugged in the values we knew and broke the volume part of the equation apart. Hence, the volume part became length x width x height. Therefore, we only had one unknown(the height(thickness)). Then we multiplied the volume by the density and divided both sides by the coefficient of the expression(27839.84mmH=0.46g(h stand for height/thickness)). This in turn gave us the variable H, which was the thickness. In the end, we had to convert from millimeters to centimeters. The important materials needed for this lab was an aluminum block, aluminum foil, ruler, pen, paper, computer, calculator, graduated cylinder, and water.
Data
We found out that the mass of the aluminum block was 80.3 g. From this we figured the volume of it by using the water displacement method which 30 mL. From this, we divided the mass by the volume and found the density, which was 2.68 g/cm^3. Then, we figured out the length and width of the aluminum foil which was 10.6 cm and 9.8 cm, respectively. From plugging this into the density equation, we found that the thickness was 0.0165 mm.
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